ThinkPHP6.0如何利用自定義驗(yàn)證規(guī)則規(guī)范的實(shí)現(xiàn)登陸

!DOCTYPE html>
html lang="en">
head>
 meta charset="UTF-8">
 meta name="viewport" content="width=device-width, initial-scale=1.0;">
 link rel="stylesheet"  rel="external nofollow" >
 link rel="stylesheet" type="text/css" href="/static/css/me.css" rel="external nofollow" >
 script src="/static/js/jquery-3.5.1.min.js">/script>
 script src="https://cdn.jsdelivr.net/semantic-ui/2.2.10/semantic.min.js">/script>
 title>博客管理登陸/title>
/head>
body>
input id="username" type="text" name="username" placeholder="登陸用戶名">
input id="password" type="password" name="password" placeholder="密碼">
script>
 $('#loginBtn').click(function () {
  let username = $('#username').val();
  let password = $('#password').val();
  $.ajax({
   url:"{:url('admin.login/login')}",
   type: 'post',
   data: {"username":username,"password":password},
   dataType: 'JSON',
   success: function (data) {
    let realData = JSON.stringify(data)
    data=eval("("+realData+")");//通過eval將（）中的字符串以json形式執(zhí)行
    if(data.code != 1) {
     alert(data.msg);
    } else {
    	window.location.href = data.data
    }
   },
   error: function (e) {
    window.location.href='/error/to500Page'
   }
  })
 })
/script>
/body>
/html>

?php
// 應(yīng)用公共文件
//show方法封裝統(tǒng)一返回給前端的JSON數(shù)據(jù)格式
function show($code, $msg = 'error', $data = [],$httpStatus = 200){
 $result = [
  "code" => $code,
  "msg" => $msg,
  "data" => $data
 ];
 return json($result,$httpStatus);
}

?php


namespace app\controller\admin;

use app\BaseController;
use think\facade\Session;
use think\Request;
use \app\model\User;

class Login extends BaseController
{
 protected $request;

 public function index(){
  return view('admin/login');
 }

 public function toAdminIndex(){
  return view('admin/index');
 }

 public function logout(){
  Session::delete('user');
  return view('admin/login');
 }

 public function __construct(Request $request){
  $this->request = $request;
  $this->request->header('Content-Type:text/html; charset=utf-8');
 }

 public function login(){
  $user = new User();
  $username = $this->request->param('username');
  $password = $this->request->param('password');
  $data = [
   'username' => $username,
   'password' => $password,
   'dto'  => ['username'=>$username,'password'=>$password], // dto 為一個(gè)數(shù)組類型
  ];
  $flag = $user->login($data); // $flag != 1 則返回錯(cuò)誤消息
  if($flag != 1){
  //show 方法在common.php 中，封裝統(tǒng)一返回前端數(shù)據(jù)格式{"code":-1,"msg":$flag,"data":null}
   return show(-1,$flag,null); 
  }
  //能到這一步說明驗(yàn)證通過,將用戶信息存入 Session 中存儲(chǔ)起來
  Session::set('user',$user->getUserByUserName($username));
  // url: '/admin.login/toAdminIndex'
  return show(1,'登陸成功!','/admin.login/toAdminIndex');
 }

}

?php


namespace app\model;


use think\exception\ValidateException;
use think\facade\Db;
use think\Model;

class User extends Model
{

 protected $table = 'user';

 public function getUserByUserName($username){
  return Db::table('user')->where('username','=',$username)->find();
 }

 public function login($data){
  try{
  //Login 是登陸驗(yàn)證器
   validate(\app\validate\Login::class)->check($data);
  } catch (ValidateException $e) {
  // 驗(yàn)證不通過則返回錯(cuò)誤消息
  // 錯(cuò)誤消息比如: "用戶名不能為空!","用戶名或密碼錯(cuò)誤!"等
   return $e->getError();
  }
  	//驗(yàn)證通過返回1,也可以是其他數(shù)字，任意,只要和 controller層對(duì)接好就行
  return 1;
 }

}

?php
declare (strict_types = 1);

namespace app\validate;

use app\model\User;
use think\Validate;

class Login extends Validate
{
 /**
  * 定義驗(yàn)證規(guī)則
  * 格式：'字段名' => ['規(guī)則1','規(guī)則2'...]
  *
  * @var array
  */
 protected $rule = [
  'username|用戶名' => 'require',
  'password|密碼' => 'require',
  'dto|用戶名或密碼' => 'checkUserExist', //checkUserExist為自定義驗(yàn)證方法
 ];

 /**
  * 定義錯(cuò)誤信息
  * 格式：'字段名.規(guī)則名' => '錯(cuò)誤信息'
  *
  * @var array
  */
 protected $message = [
  'dto.checkUserExist' => '用戶名或密碼錯(cuò)誤!'
 ];

	// $value 為 [
	//			 "username" => username,
	//   "password" => password,
	//   ]
 public function checkUserExist($value){
  $model = new User();
  $user = $model->getUserByUserName($value['username']);
  if($user == null){
   return false;
  }
  //前端傳過來的密碼需要 加密后 才可以正確與數(shù)據(jù)庫(kù)中的密碼匹配
  if($user['password'] != md5($value['password'])){
   return false;
  }
  return true;
 }

}